Calculating Satellite Orbit Height Above Earth's Surface

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SUMMARY

The discussion focuses on calculating the height of communications satellites above Earth's surface, specifically those in a geostationary orbit that completes one rotation every 24 hours. The relevant equation is derived from the formula GM/(4π²)T², where G represents the gravitational constant, M is the mass of the Earth, and T is the orbital period. Participants clarify that the mass (M) in the equation refers to the mass of the Earth, essential for determining the satellite's orbit radius.

PREREQUISITES
  • Understanding of gravitational physics and orbital mechanics
  • Familiarity with the gravitational constant (G)
  • Knowledge of the mass of the Earth (M)
  • Basic proficiency in algebra and equations involving π
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  • Research the gravitational constant (G) and its significance in orbital calculations
  • Learn about geostationary orbits and their characteristics
  • Explore the derivation of Kepler's laws of planetary motion
  • Study the effects of altitude on satellite communication signals
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Aerospace engineers, physics students, and professionals involved in satellite communications and orbital mechanics will benefit from this discussion.

livblue23
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Homework Statement


Communications satellites are placed in orbits such that they rotate the Earth once every 24.0 hours. Determine how high above the Earths surface these satellites must be placed.


Homework Equations


GM/4(3.14 squared) times T squared


The Attempt at a Solution


so i know that first i have to get the radius by using GM/4(3.14 squared) times T squared, and then subract the Earth's radius from that, but what would be the M in that equation?
 
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Hi livblue23! :smile:

(have a pi: π :wink:)

I'm not sure what equation you're using,

but anyway M would be the mass of the Earth. :smile:
 

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