Calculating Shear and Tensile force in a rivet at an angle

[Carbretta]

Homework Statement

A Load F of 50kN is applied to the tensile member shown in figure 3, and is carried at the joint by a single rivet. The axis of the rivet is at 30 degrees to the line of action of the load F

Relevant Equations

a) Calculate the tensile and shear stresses in a 20mm diameter rivet
b) Calculate the tensile strain in a 20mm diameter rivet
c) If the ultimate tensile stress of the rivet material is 350MPa and its modulus of elasticity is 150GPa find the safety factor the the above rivet in operation

Hi all!

I have used this forum a few times and it has been very helpful, however now I am stuck. I have completed the question above however I have conflicting information regarding the Tensile and Shear force being applied to the rivet. I use the following calculation for this:

Shear Force: 50sin30
Tensile Force: 50cos30

However the lecturer has informed me that the calculation only needs to be done for the shear force, and that the Tensile force would simply be 50kN (The force being applied). This is in contradiction to another post I have seen with a very similar question on this forum. I am struggling to visualise and understand how this would work out. If someone could explain this to me I would be very grateful as I don't just want to give a correct answer, I would like to understand why as well. Thanks in advance!

 

[PhanthomJay]

Your answer is correct. I’m not sure of the reasoning behind your lecturer’s response. The total applied force vector is 50 kN in the horizontal direction. The vector component parallel to the plane of the cross section is the shear force, and the vector component perpendicular to the plane of the cross section is the tensile force. That is what you have correctly done. Ask him what he meant.

By the Way, welcome to PF as a member!