Tensile and shear stress in 10mm rivet

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Discussion Overview

The discussion revolves around calculating tensile and shear stresses in a 10mm diameter rivet subjected to a load of 3kN at a 45-degree angle. Participants explore the methodology for resolving forces and calculating stresses, addressing potential errors in the initial calculations.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant calculates the shear force as 2.121 kN and the tensile force as 2.12 kN, leading to a tensile stress calculation of approximately 27 MN/m².
  • Another participant questions the clarity of the original post, suggesting that the angle may have been misinterpreted and indicating a discrepancy in the drawing.
  • There is a mention of a book solution that supports the use of a 45-degree angle, which aligns with the initial calculations presented by the first participant.
  • One participant expresses confusion over their tutor's feedback, seeking clarification on their method and calculations.
  • Another participant confirms that the initial calculations agree with the book solution but emphasizes the need for proper notation in reporting the stress values.

Areas of Agreement / Disagreement

Participants generally agree on the calculations for tensile and shear stress based on the provided angle, but there is disagreement regarding the correctness of the initial interpretation of the angle and the tutor's feedback. The discussion remains unresolved regarding the tutor's critique.

Contextual Notes

There are indications of potential misinterpretation of the angle in the problem statement, which may affect the calculations. The discussion also highlights the importance of clear presentation in mathematical workings.

Who May Find This Useful

Students studying mechanics of materials, particularly those dealing with stress analysis in structural components like rivets, may find this discussion relevant.

chris78
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Homework Statement


A load P of 3kN is applied to the tensile member shown and is carried at the joint by
a single rivet. The angle of the shear joint is 45 degrees to the axis of the load. Calculate
the tensile and shear stresses in a 10mm diameter rivet

Homework Equations

The Attempt at a Solution



Work out Shear force:
[/B]
Shear force 3sin45=2.121kn

Work out tensile force:

Tensile force=3cos45=2.12kn

Tensile stress= force/area

=2121.3/7.853x10^-5
=27009236.08 nm/^2
=27 mn/m2

Shear stress will be the same

I have atttached an image of the question and also my workings out. I am being told that this is incorrect by my tutor...but have been racking my brains to why! Is the resolved triangle in my workings wrong?

Any help would be brilliant as I am not sure where/if I am going wrong!

Thanks
 

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Well, post what you have done ! An illegible sunny picture doesn't help.

[aside:] And don't trust the exercise composer: he/she tries to sell you a 45 degree angle that's clearly drawn at 60 degrees :smile:
 
I have posted my workings...within the post as well as 'illegible' scribblings...the problem states 45 degrees ?
 
chris78 said:
I have posted my workings...within the post as well as 'illegible' scribblings...the problem states 45 degrees ?
The book solution uses 45 degrees ...answer given is correct for shear and tensile stress. Your answer agrees except be sure to write it properly as 27 MN/m2.
 
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Hi there

Thankyou for you reply...when I handed this in my tutor said I was wrong..but I have been racking my brains to see why...that's why I posted a picture of my workings with my vector triangle to make sure my method is correct
 
PhanthomJay said:
The book solution uses 45 degrees ...answer given is correct for shear and tensile stress. Your answer agrees except be sure to write it properly as 27 MN/m2.
Thanks for your help...i have just posted another similar question regarding this subject...is it possible you could have a look at it for me,and tell me if I am on the correct lines? Again,thanks for your help.
 

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