Calculating Slip and Number of Poles in Induction Motor

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SUMMARY

The discussion focuses on calculating the slip and number of poles in an induction motor supplied by an 8-pole, 3-phase alternator running at 750 RPM. The slip is determined using the formula s = (ns - nm) / ns, where ns is the stator synchronous speed and nm is the rotor speed. The frequency of the induced voltage from the alternator is calculated using f = (NP) / 120, where N is the alternator's RPM and P is the number of poles. Understanding these calculations is essential for determining the operational characteristics of the induction motor.

PREREQUISITES
  • Understanding of synchronous machines and their operation
  • Knowledge of induction motor principles and slip calculation
  • Familiarity with electrical frequency calculations
  • Ability to apply formulas for synchronous speed and pole calculation
NEXT STEPS
  • Learn how to calculate stator synchronous speed using frequency and pole count
  • Study the relationship between slip and motor performance in induction motors
  • Explore the role of alternators in supplying power to induction motors
  • Investigate the effects of varying the number of poles on motor speed and efficiency
USEFUL FOR

Electrical engineers, motor control specialists, and students studying electrical machines will benefit from this discussion, particularly those focused on induction motor performance and alternator interactions.

prat
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an 8 pole 3 phase alternator is coupled to a prime mover running at 750 rpm.it supplies an induction motor which has a full load of 960rpm find the number of poles of the motor and the slip

i think the induction motor would work as a generator we can find slip by usin

s=(ns-nm)/ns

where ns=stator synchronous speed and nm is rotor speed or frequency

i know that no of poles can be found by

f=nsP/120 where P is the no of poles
f here is the frequency

but how to sum these formulas and use them to get appropriate result
 
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prat said:
an 8 pole 3 phase alternator is coupled to a prime mover running at 750 rpm.it supplies an induction motor which has a full load of 960rpm find the number of poles of the motor and the slip

i think the induction motor would work as a generator we can find slip by usin

s=(ns-nm)/ns

where ns=stator synchronous speed and nm is rotor speed or frequency
I don't think you're interpreting the problem correctly. There are two machines involved, the alternator (a synchronous machine that has no slip), and the induction motor (that has slip).

The prime mover (mechanical) is attached to the alternator mechanically. The alternator is working as a (synchronous) generator. It produces electricity.

The induction motor is connected electrically (not mechanically) and acts a motor. We can come back to the induction motor later.

First, one must calculate the frequency of the induced voltage produced by the alternator.
i know that no of poles can be found by

f=nsP/120 where P is the no of poles
f here is the frequency

but how to sum these formulas and use them to get appropriate result
First we must calculate the frequency of the induced voltage produced by the alternator (before we even consider the induction motor). Use
f = \frac{NP}{120 [\mathrm{s/min}]}
where
f: frequency of induced voltage, in units of Hz.
N: rotational speed of alternator's rotor, in units of RPM.
P: number of poles in Alternator.

With that, you should be able to calculate the frequency of the induced voltage.

Your next step is to calculate the stator synchronous speed. There is a formula for that and it is a function of the frequency of induced voltage, and the number of poles in the induction motor. (You haven't listed the equation, but there is one.) Once you find the equation, pick a value for the number of poles that makes sense.

After that, you can calculate the slip.

Good luck! :smile:
 

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