The discussion revolves around calculating the specific heat capacity of a metal when it is immersed in water, involving the principles of heat transfer and thermal equilibrium. The problem presents specific masses and temperatures for both the metal and water, leading to a query about the unknown variable of the metal's specific heat capacity.
The discussion is ongoing, with some participants providing guidance on the correct equation to use and prompting further exploration of temperature changes. There is no explicit consensus on the solution, and multiple interpretations of the attempts are being considered.
There are indications of typos in the attempts, and the original poster's attempts at solutions are noted as insufficient by other participants. The discussion is framed within the constraints of a homework assignment, emphasizing the need for clarity in reasoning and calculations.
Heat gained by metal = heat lost by water.rrosa522 said:Homework Statement
When 1.25 kg of a cold metal at a temperature
of 263 K was immersed in 1.43 kg of water at
a temperature of 365 K, the final temperature
was 336 K. What is the specific heat capacity
of the metal?
Homework Equations
Q=mc∆t
-Q=Q[/B]
The Attempt at a Solution
The answer should be 1.90KJ(kg*K)[/B]
rrosa522 said:
The Attempt at a Solution
The answer should be 1.90KJ(kg*K)[/B]
And there are a couple of typos as well, it should be written as 1.90 kJ/(kgK)CWatters said:That's not an attempt at a solution.