Calculating Speed of Sound in Water Given Torpedo Impact Data

Click For Summary
To calculate the speed of sound in water based on the torpedo impact data, first determine the time it takes for the torpedo to reach the target, which is 100 seconds at a speed of 20 m/s over 2000 m. The total time from firing to hearing the sound is 101.4 seconds, meaning the sound takes 1.4 seconds to travel back. By using the formula speed = distance/time, the distance sound travels in 1.4 seconds can be calculated. This leads to the conclusion that the speed of sound in water is approximately 1428.57 m/s. The discussion emphasizes the importance of correctly interpreting the time intervals and distances involved in the problem.
skybird
Messages
1
Reaction score
0

Homework Statement


A torpedo fired from a submerged submarine is propelled through the water with a speed of 20.00 m/s and explodes upon impact with a target 2000.0 m away. If the sound of the impact is heard 101.4 s after the torpedo was fired, what is the speed of sound in water? (torpedo is held at a constant speed by propeller)


Homework Equations


speed=d/t


The Attempt at a Solution


I started by reading through the question and thought, if the torpedo travels 20 m/s, and it went 2000 m, then it would be traveling the length in 100 seconds. From there i thought that since it takes 101.4 s for the sound to reach the listener, I could divide 100 by 101.4, concluding that the speed of sound was 1.014 m/s. I think i am completely wrong in how to solve this problem. Please help!
 
Physics news on Phys.org
If you divide 100 seconds by 101.4 seconds, what are the units of the quotient?

Now, you know how far the sound travels and how long it takes to travel. Don't you think that's a better approach?
 
Thread 'Correct statement about size of wire to produce larger extension'
The answer is (B) but I don't really understand why. Based on formula of Young Modulus: $$x=\frac{FL}{AE}$$ The second wire made of the same material so it means they have same Young Modulus. Larger extension means larger value of ##x## so to get larger value of ##x## we can increase ##F## and ##L## and decrease ##A## I am not sure whether there is change in ##F## for first and second wire so I will just assume ##F## does not change. It leaves (B) and (C) as possible options so why is (C)...

Similar threads

Replies
7
Views
2K
  • · Replies 16 ·
Replies
16
Views
6K
Replies
2
Views
2K
  • · Replies 7 ·
Replies
7
Views
5K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
5K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 12 ·
Replies
12
Views
4K
Replies
3
Views
5K
  • · Replies 1 ·
Replies
1
Views
1K