A submarine of mass 2.5 x 10^6 kg and initially at rest fires a torpedo of mass 260 kg. The torpedo has an initial speed of 100.4 m/s. What is the initial recoil speed of the submarine? Neglect the drag force of the water.
The Attempt at a Solution
mass one = 2.5x10^6 (submarine)
velocity one = 0 (sub isnt moving)
mass two = 260 (torpedo)
velocity two = 100.4 (torpedo)
How can I find the recoil? I thought maybe it'd just be velocity one (instead of zero solve for x)
v1 = (260*100.4)/2.5x10^6 = -0.01 m/s
But that's wrong...
what am i missing?