A 19 kg box slides down a frictionless ramp of 4.5 m length and 1.3 m height, reaching a speed calculated through conservation of mechanical energy. The potential energy (PE) at the top, given by the formula PE = mgh, equals the kinetic energy (KE) at the bottom, expressed as KE = 1/2 mv². By equating these energies, the velocity at the bottom of the ramp is determined to be the square root of 2 x 9.8 x 1.3, yielding a definitive speed result in meters per second.
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That looks like a calculation of the PE at the top of the ramp: PE = mgh. (The units will be Joules.) Which happens to be the total mechanical energy, since it starts from rest. Since energy is conserved, this also equals the KE at the bottom of the ramp. ({KE} = 1/2 m v^2)billyghost said:19 x 1.3 x 9.8 ?