Calculating Spring Constant from Conservation of Energy Equation

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SUMMARY

The discussion focuses on calculating the spring constant (k) using the conservation of energy equation for a 1 kg mass suspended from a spring. The initial velocity is 3.0 m/s, and the final velocity is 1.5 m/s, with initial and final heights of -0.1 m and -0.25 m, respectively. The conservation of energy equation incorporates kinetic energy, gravitational potential energy, and elastic potential energy. The correct approach involves determining the initial and final displacements of the spring and applying them in the energy equation to solve for the spring constant.

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  • Understanding of conservation of energy principles
  • Familiarity with kinetic and potential energy equations
  • Knowledge of Hooke's Law and spring constants
  • Basic algebra for solving equations
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  • Review the conservation of energy equation in physics
  • Study Hooke's Law and its application in spring mechanics
  • Practice problems involving energy transformations in mechanical systems
  • Learn about the relationship between mass, displacement, and spring constant
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Homework Statement



A mass 1 kg mass is hung from a spring.
Calculate the spring constant from the given data. Velocity initial= 3.0 m/s Velocity final= 1.5 m/s. The initial height traveled is 0.1 meters and the final is 0.25 meters. These height values will be negative since i picked my starting point at the origin so they have moved below the X making them negative.



Homework Equations


I know i am supposed to use the conservation of energy equation with the potential elastic factored into the total PE. the equation would be (1/2*m*v^2)+(mgh)+1/2*k*x^2)=(1/2*m*v^2)+(mgh)+1/2*k*x^2) where the left is the initial and the right is the final. However i keep getting the wrong answer. I think I am doing a simple algebraic error in my calculations. any guidance is appreciated


The Attempt at a Solution

 
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I think you have to determine the initial displacement of the spring under the static load:

Xo = mg / K

Then final displacement is:

Xf = mg / K - \DeltaX

Where \DeltaX = 0.25m - 0.1m = 0.15m

Put that in your equation and do the transformations and it should give you the correct answer.
 

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