Calculating Spring Force with a Man's Jump and Platform Compression

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SUMMARY

The discussion focuses on calculating the spring force exerted by a platform when an 80 kg man jumps from a height of 2 meters and compresses the springs by 0.2 meters. The key equations utilized include the conservation of energy principle, represented as mgΔh = 1/2 kx² + mgΔh + 1/2 mv², and the spring force equation F = -kx. The user seeks to determine the man's speed at a compression of 0.1 meters and the platform's compression if the man steps gently onto it. The solution involves calculating the spring constant k using the maximum compression and the man's weight.

PREREQUISITES
  • Understanding of gravitational potential energy and kinetic energy
  • Familiarity with Hooke's Law (F = -kx)
  • Basic knowledge of conservation of energy principles
  • Ability to solve quadratic equations
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  • Calculate the spring constant k using the maximum compression of 0.2m
  • Learn how to apply conservation of energy in dynamic systems
  • Explore the relationship between potential energy and kinetic energy in mechanical systems
  • Investigate the effects of varying mass and height on spring compression
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Physics students, mechanical engineers, and anyone interested in understanding dynamics and energy conservation in spring systems.

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Homework Statement


An 80 kg man jumps from a height of 2m onto platform mounted on springs. As the springs compress the platform is pushed down a maximum distance of 0.2m below its initial position, and it rebounds.
a) What is the man's speed at the instant the platform depressed 0.1m?
b) If the man had just stepped gently onto the platform how much would it have been pushed down?


Homework Equations





The Attempt at a Solution


A) I am stuck. I think maybe Ua + Ka = Ub + Kb
and mgh = 1/2kmv2
but then I don't know how to get k and v.

B) ΣFy = 0
ΣFy = Fs - mg
Fs = kd
0 = kd - mg
kd = mg
Now what?
 
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potential + kinetic = potential + kinetic
This is right.

So initially he has all gravitational potential (when he's 2m from the spring) no kinetic and no spring potential.

The moment he hits the board, he has some gravitational potential, some kinetic and is just about to receive some spring potential.

When he is 0.1 m into it he has some gravitational potential, some kinetic and some spring potential.

I'll give you this sum:

mg\delta h = \frac{1}{2} kx^2 + mg\delta h + \frac{1}{2} mv^2

Solving for v of course.

You can get k, by the information given. Maximum compression = 0.2m and you have his mass (80kg) and you have the acceleration of gravity (-9.81ms-2).

Does F=-kx ring a bell?

Let me know how you go.
 
potential + kinetic = potential + kinetic
This is right.

So initially he has all gravitational potential (when he's 2m from the spring) no kinetic and no spring potential.

The moment he hits the board, he has some gravitational potential, some kinetic and is just about to receive some spring potential.

When he is 0.1 m into it he has some gravitational potential, some kinetic and some spring potential.

I'll give you this sum:

mg\Delta h = \frac{1}{2} kx^2 + mg\Delta h + \frac{1}{2} mv^2

Solving for v of course.

You can get k, by the information given. Maximum compression = 0.2m and you have his mass (80kg) and you have the acceleration of gravity (-9.81ms-2).

Does F=-kx ring a bell?

Let me know how you go.
 

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