ΣF , ω=√(k/m), f=w/(2pi)
The Attempt at a Solution
I figured since the only forces acting on the block is the Spring force and a normal force in the downward position. Not a hundred percent sure of this though.
ΣFy= Fn - Fg - fs (static) = ma = 0
ΣFy= fs-Fs (Spring) - Fn = ma = 0
Equating both Spring and Disc:
fs-Fs-Fg-fs = 0
--> ky = mg
k= mg / y= (.002kg)(9.8m/s^2) / (.08m) = .245 N/m
w= sqrt (k/m) = sqrt ((.245N/m)/(.010 kg+.002kg)) = 4.52 rad/s
f= .719 Hz
Is this correct for part a? Can somebody please assist me, thank you!