Bungee jump height/spring energy

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Homework Help Overview

The problem involves designing a bungee jumping platform, focusing on the dynamics of a jumper attached to a bungee cord. The jumper's mass, the unstretched length of the rope, and the spring constant are provided, with the goal of determining how far below the platform the jumper will descend during the jump.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the relationships between potential energy, kinetic energy, and spring energy, attempting to set up equations to model the jump dynamics. There is a focus on defining variables such as H, L, h, and d, and clarifying their meanings in the context of the problem.

Discussion Status

Some participants are providing guidance on the setup of equations and questioning the definitions of variables. There is an ongoing exploration of the relationships between the energies involved and the implications of the definitions used. Multiple interpretations of the variables are being discussed, indicating a productive exchange of ideas.

Contextual Notes

Participants note that the original poster's equations may contain errors and that there are too many unknowns in the setup. The discussion includes clarifications about the potential energy reference point and the conditions under which the rope is stretched.

Matt123456789
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Homework Statement


Imagine that you have been given the job of desiging a new bungee jumping platform. Customers of mass 53.0 kg will step off a platform, attached to a rope of unstretched length 52.6 m and spring constant 17.0 n/m.

How far below the platform will the end of end of the rope get during a jump? This is the lowest point it will ever reach, not where it settles down.

You may assume that g=9.8 m s-2.

Homework Equations


PE=mgh
KE=0.5mv^2
Spring energy=0.5kd^2

The Attempt at a Solution


- Set the distance from platform to when rope first goes taut as H, distance from H to to lowest point as L
- rearranged equations to get mgh=0.5kL^2-mgL
- also tried mgh=0.5kd^2 and solve for d
- got 90.6 and 91.5, both wrong, no idea what to do now
 
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Matt123456789 said:
mgh=0.5kL^2-mgL
I think you're on the right track.
What is answer that is given, which makes you think you're answer is wrong?
 
Matt123456789 said:

The Attempt at a Solution


- Set the distance from platform to when rope first goes taut as H, distance from H to to lowest point as L
- rearranged equations to get mgh=0.5kL^2-mgL
You explained the meaning of H and L, but what are h and d?
 
Last edited:
The answer i submit is checked and I am told if I am wrong or right, but not what the actual answer is.

h is the total height, and d i think is meant to be L
 
Matt123456789 said:
The answer i submit is checked and I am told if I am wrong or right, but not what the actual answer is.

h is the total height, and d i think is meant to be L
In this case, your first equation is wrong, and there are too many unknowns in the second equation.

If you count the potential energy zero at the height of the platform, what is the PE at the deepest position, at depth h? How much is the rope stretched then? What is the elastic energy? What is the speed?
 
Matt123456789 said:
h is the total height,
Do you mean the length of the rope?
If so I don't see why your 1st equation could be wrong.
 
Suraj M said:
Do you mean the length of the rope?
If so I don't see why your 1st equation could be wrong.
The OP said that h was the total (stretched ) length of the rope, that is, h=H+L:. The equation
mgh=0.5kL^2-mgL
is wrong.
 
ehild said:
The OP said that h was the total (stretched ) length of the rope
oh! I thought he said it was the length of the rope,thats why i put the condition
Suraj M said:
Do you mean the length of the rope?
If so ...
I misunderstood, sorry
 

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