- #1

Matt123456789

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## Homework Statement

Imagine that you have been given the job of desiging a new bungee jumping platform. Customers of mass 53.0 kg will step off a platform, attached to a rope of unstretched length 52.6 m and spring constant 17.0 n/m.

How far below the platform will the end of end of the rope get during a jump? This is the lowest point it will ever reach, not where it settles down.

You may assume that g=9.8 m s-2.

## Homework Equations

PE=mgh

KE=0.5mv^2

Spring energy=0.5kd^2

## The Attempt at a Solution

- Set the distance from platform to when rope first goes taut as H, distance from H to to lowest point as L

- rearranged equations to get mgh=0.5kL^2-mgL

- also tried mgh=0.5kd^2 and solve for d

- got 90.6 and 91.5, both wrong, no idea what to do now