Calculating Tarzan's Height on a Vine at 8.0 m/s - Grade 11 Question

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SUMMARY

The discussion revolves around calculating the height Tarzan reaches on a vine after jumping at a speed of 8.0 m/s. The relevant equation of conservation of energy (COE) is provided: 0 = 0.5mvf² - 0.5mvi² + mgzf - mgzi. With vf set to 0 at the top of the swing and the initial height (zi) set to 0, the equation simplifies to 0 = -0.5mvi² + mgzf. The mass of Tarzan is specified as 60 kg, which is crucial for solving the equation for zf, the height above the bottom of the swing.

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LiquidIce
The question is something like this I am not sure exactly because it was on my test.

Tarzan is running at 8.0 m/s and jumps onto a vine. How high above the bottom of his swing will he go ?

Plz help i have no clue how to do this
 
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Put what you have into a COE equation.
0= .5mvf^2 - .5 mvi^2 + mgzf - mgzi

vf=0 at top of swing
zi=0 in my reference frame

so 0= -.5 mvi^2 + mgzf

and solve for zf.
 
um...whats zf stand for
 
What you are looking for. (How high above the bottom of his swing will he go)

You know what the others stand for right?
 
i just found out that they also gave the mass of tarzan in the question the mass is 60kg
 

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