Calculating Temperature Increase of a Rubber Ball Dropped from a Building Roof

[rijo664]

idk if i did this correctly so far so here goes.

The question states

A large rubber ball (8.80 kg) is fired straight down from the roof of a building from a spring loaded mechanism that stored 987 J of elastic potential energy. The building roof is 14.0 meters above ground. The rubber bounces straight back up (noiselessly--don't ask how) back to a height of 9.5 meters. Assuming no heat is lost to the air around the ball, calculate the increase in temperature of the ball (Specific Heat of rubber is 1250 J/kgK

What i did was:
M= 8.80kg
Spring Potential Energy= 987 J
Building roof= 14.0 m
The rubber bounces back up= 9.5 m
Specific Heat of rubber is 1250 J/kgK

1) I found the Change in Height= 14.0-9.5= 4.5m
2) Then i used the gravitational potential energy formula which is
(mass)(g)(the change in height)
3)g=10
4)Gravitational Potential Energy= (8.80)(10)(4.5)
gravitational potential energy= 396 J

That is what i got for my gravitational potential energy then i used my spring potential energy which is 987 J and added that with 396 J and got 1383.
I believe that the 1383 J is the heat and i should find the change in temp. am i right or am i wrong here

 

[learningphysics]

Looks good to me.

 

[dynamicsolo]

That is what we were getting at earlier. Why didn't you add that to your previous thread for this problem [ https://www.physicsforums.com/showthread.php?t=185227 ], rather than start another one?