# Did i do this problem correctly

idk if i did this correctly so far so here goes.

The question states

A large rubber ball (8.80 kg) is fired straight down from the roof of a building from a spring loaded mechanism that stored 987 J of elastic potential energy. The building roof is 14.0 meters above ground. The rubber bounces straight back up (noiselessly--don't ask how) back to a height of 9.5 meters. Assuming no heat is lost to the air around the ball, calculate the increase in temperature of the ball (Specific Heat of rubber is 1250 J/kgK

What i did was:
M= 8.80kg
Spring Potential Energy= 987 J
Building roof= 14.0 m
The rubber bounces back up= 9.5 m
Specific Heat of rubber is 1250 J/kgK

1) I found the Change in Height= 14.0-9.5= 4.5m
2) Then i used the gravitational potential energy formula which is
(mass)(g)(the change in height)
3)g=10
4)Gravitational Potential Energy= (8.80)(10)(4.5)
gravitational potential energy= 396 J

dynamicsolo
Homework Helper
What i did was:
M= 8.80kg
Spring Potential Energy= 987 J **
Building roof= 14.0 m
The rubber bounces back up= 9.5 m
Specific Heat of rubber is 1250 J/kgK

1) I found the Change in Height= 14.0-9.5= 4.5m
2) Then i used the gravitational potential energy formula which is
(mass)(g)(the change in height)
3)g=10
4)Gravitational Potential Energy= (8.80)(10)(4.5)
gravitational potential energy= 396 J

Don't forget that the ball wasn't dropped from rest from the top of the building; it was *launched* by a spring gun. What was the ball's initial kinetic energy when it first started down to the ground? What was the total mechanical energy it had when it hit the ground? How much total mechanical energy did it have at the end of its rebound? Did all of the mechanical energy loss go into heating the ball?

well i don't have the velocity to use the kinetic energy formula u got any advice for that.

dynamicsolo
Homework Helper
(Hmm, the edit function doesn't work with this browser...) I also wanted to say that what you have calculated so far is the *change* in the gravitational potential energy of the ball. Your value looks correct. (Is it OK to use g=10? I'm just asking whether your grader accepts this level of precision.) What *else* do you need?

dynamicsolo
Homework Helper
well i don't have the velocity to use the kinetic energy formula u got any advice for that.

You don't need to know the velocity of the ball at any point. You only need to consider the amounts of each type of energy (kinetic; gravitational potential; heat or internal). It's the change in internal energy of the ball that is going to cause the temperature change.

i got that but i need the formula though

dynamicsolo
Homework Helper
i got that but i need the formula though

The formula for kinetic energy is KE = (1/2)M(v^2). What do you need it for?

Chi Meson