You are standing on top of a building. Two balls are thrown

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SUMMARY

In the discussion, two balls are thrown from a building: one upwards at 10 m/s and the other downwards at the same speed. The ball thrown downwards will reach the ground first due to the effects of gravity, which accelerates both balls at 9.8 m/s². Although the upward-thrown ball gains gravitational potential energy, it does not accelerate faster than the downward-thrown ball. The key takeaway is that the initial velocity and direction of the throw significantly influence the time of descent, confirming that the downward-thrown ball arrives first.

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  • Understanding of kinematic equations, specifically v² = u² + 2as
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  • Basic principles of kinetic energy and motion
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One ball is thrown upwards at 10 m/s, the other is thrown straight down (not dropped) also at 10 m/s. Which ball arrives first?

This is more of a theoretical question than anything. I know the relevant equations such as v^2=u^2 +2as, but I was thinking that the height of the building has to count for something because the ball traveling straight upwards would gain gravitational potential energy. But "common sense" dictates that the ball thrown straight down would arrive at the floor first.
 
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Remember that everything accelerates (generally) at 9.8 m/s^2 towards the ground due to gravity. While the higher ball thrown up will have a greater gravitational potential it will also have a higher kinetic energy when it hits the ground, this is because it has been falling a greater distance. That does not mean that it will manage to accelerate any faster than the ball thrown downwards.
 

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