Calculating Tension and Total Force in Equilibrium Torque System

[joemama69]

Homework Statement

Note Picture...

A uniform beam, 5.00 m long with a mass of 2.00 x 103 kg, is held against a wall in the position shown by a hinge and a horizontal steel wire attached to its end.



a) Find the tension in the wire.
b) Find the magnitude of the total force supplied by the hinge.

The Attempt at a Solution

the only forces for the torque is the mass of the beam perpendicular to the beam as well as the tension of the cable

beam torque = mgdcosQ = 2000(9.8)(2.5)(cos20)
tension torque = T_xsinQ this is where I am a littel confused because the tension is in the x direction but the torque should be perpindicular to the beam so its confusing me.

2000(9.8)(2.5)(cos20) = T_xsinQ...T_x = 135426.28

is this correct
T

 

[rl.bhat]

Torque due to the tension is T*sinθ*L where L is the length of the beam.

 

[joemama69]

oh right right...

2000(9.8)(2.5)(cos20) = T_x(5)sin20...T_x = 26926.87 N

is this correct