The discussion focuses on calculating the tension in a rope supporting a bucket that is decelerating at a constant rate of 0.640 m/s². The weight of the bucket is given as 22.0 N. The correct approach involves using Newton's second law (F=MA) to derive the mass of the bucket as 2.24 kg and then calculating the tension in the rope (T) as 23.39 N by considering both the gravitational force and the deceleration. The initial misstep of adding accelerations is corrected by emphasizing the importance of drawing a force diagram.
PREREQUISITESStudents studying physics, particularly those focusing on mechanics, as well as educators seeking to clarify concepts related to tension and forces in motion.
badshar said:Homework Statement
A bucket is lifted up by a rope, slowing down at a constant rate of 0.640 m/s^2. Find the tension in the rope if the bucket weighs 22.0 N.
Homework Equations
F=MA
Fg(gravity)=M*G(gravitational force)
The Attempt at a Solution
9.8 m/s^2 + 0.640 m/s^2 = 10.44 m/s^2
22N=M*9.8m/s^2
M=2.24 kg
Ft=MA
Ft=2.24 kg * 10.44 m/s^2
Ft=23.39 N