Calculating Tension in Ropes A & B

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SUMMARY

The discussion focuses on calculating the tension in two ropes supporting a 1 kg ball and a 2 kg ball, both accelerating upwards at 4.0 m/s². The tension in rope A is calculated to be 41.4 N, while the tension in rope B is determined to be 27.6 N. The calculations incorporate gravitational force (Fg) and the net force due to acceleration (ma). The participants confirm the correctness of the calculations and emphasize the importance of considering all forces acting on the system.

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Homework Statement


I have a 1 kg ball hanging from rope A, and a 2 kg ball connected to the 1 kg ball by rope B. They are accelerating up at 4.0 m/s^2. I need to know the tension in rope A and rope B.


Homework Equations


Tension = Fg + ma ?


The Attempt at a Solution


Rope A: (1 kg + 2 kg) * (9.8 m/s^2) + (1 kg + 2 kg) * (4 m/s^2) = 41.4 N
Rope B: (2 kg) * (9.8 m/s^2) + (2 kg) * (4 m/s^2) = 27.6 N

Am I doing this correctly?
 
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I think since the ropes are accelerating in the vertical direction , the sum of all forces acting on the ropes with the attached ball will be equal to an accelerating force, not zero. Have you sketched a free body diagram of all the forces acting upon the two ropes? .
 
Last edited:
jamessmith said:

The Attempt at a Solution


Rope A: (1 kg + 2 kg) * (9.8 m/s^2) + (1 kg + 2 kg) * (4 m/s^2) = 41.4 N
Rope B: (2 kg) * (9.8 m/s^2) + (2 kg) * (4 m/s^2) = 27.6 N

Am I doing this correctly?
Looks good! :smile:

p.s. Welcome to Physics Forums.
 

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