Calculating Tension on Two Wires Attached to 200g Sphere

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SUMMARY

The discussion focuses on calculating the tension in two wires attached to a 200 g sphere revolving in a horizontal circle at a speed of 7.80 m/s. The equations used for tension are T + mg = mv²/r for the upper wire and T - mg = mv²/r for the lower wire, where T represents tension, m is mass, g is gravitational acceleration, v is velocity, and r is radius. The participant initially calculated tensions of 22.4 N and 26.3 N but found these values incorrect. A critical factor, the 30-degree angle of the wires with the vertical, was highlighted as potentially overlooked in the calculations.

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Two wires are tied to the 200 g sphere shown in figure. The sphere revolves in a horiIzontal circle at a constant speed of 7.80 m/s. The diagram shows a ball with two wires, each 1 m in length with a radius of .5 m

What is the tension in the upper wire?


What is the tension in the lower wire?

So, what i thought i would do was

T + mg = mv^2/r for the tension of the upper wire and

where T = 22.4

T - mg = mv^2/r for the tension of the lower wire..but after doing it i am not getting the right answers

and T = 26.3 but apparently neither are the right answers...
 
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lmc489 said:
Two wires are tied to the 200 sphere shown in figure. The sphere revolves in a horiIzontal circle at a constant speed of 7.80 . The diagram shows a ball with two wires, each 1 m in length with a radius of .5 m

What is the tension in the upper wire?What is the tension in the lower wire?

So, what i thought i would do was

T + mg = mv^2/r for the tension of the upper wire and

where T = 22.4

T - mg = mv^2/r for the tension of the lower wire..but after doing it i am not getting the right answers

and T = 26.3 but apparently neither are the right answers...

Have you properly accounted for the 30 degree angle the wires make with the vertical?
 

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