Calculating Terminal Velocity for a Ping Pong Ball: A Simple Equation

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SUMMARY

The terminal velocity of a ping pong ball can be calculated using the drag force equation, where the drag coefficient (Cdrag) is approximately 0.44. The formula for drag force is Fdrag = Cdrag * ρair * π * D2 * V2 / 8, balancing with the gravitational force (mg) to find terminal velocity (VT). Experimentally, terminal velocity can be verified by dropping the ball from a height and timing the fall, although theoretical calculations using known values for diameter, mass, and air density may yield more accurate results.

PREREQUISITES
  • Understanding of basic physics concepts, including forces and motion.
  • Familiarity with the drag coefficient and its significance in fluid dynamics.
  • Ability to perform basic measurements and calculations involving height, time, and velocity.
  • Knowledge of standard atmospheric conditions and their impact on air density.
NEXT STEPS
  • Learn how to calculate terminal velocity for different shapes and sizes using fluid dynamics principles.
  • Explore the effects of varying air density on terminal velocity in different environmental conditions.
  • Investigate experimental methods for measuring drag coefficients of various objects.
  • Study the relationship between mass, surface area, and terminal velocity in spherical objects.
USEFUL FOR

Students in physics, educators conducting experiments on motion, and hobbyists interested in aerodynamics and fluid dynamics principles.

profaith
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hey how do you find terminal velocity? let say if you need to find the terminal veolcity of a ping pong ball? anyone has any ideas? what kind of experiment can i conduct?
 
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profaith said:
hey how do you find terminal velocity? let say if you need to find the terminal veolcity of a ping pong ball? anyone has any ideas? what kind of experiment can i conduct?
The terminal velocity of spheres like ping pong balls are fairly easy to compute and measure. The motion of such a sphere in still air at standard atmospheric temp & pressure will have a Drag Coefficient approx constant at C_{drag} = (0.44). The force F_{drag} due to aerodynamic drag ("air resistance") when the sphere falls thru air under those conditions is given by:

:(1): \ \ \ \ F_{drag} \ = \ C_{drag} \, \rho_{air} \,<br /> \pi \, D^{2} \, V^{2} /8

where "ρair" is the air density, "D" the sphere diameter, and "V" its fall velocity thru still air. The sphere will rapidly reach terminal velocity at the "VT" such that Drag Force exactly balances gravitational force on the sphere, namely its weight "mg":

:(2): \ \ \ \ F_{drag} \ = \ m \, g

:(3) \ \ \ \ \Longrightarrow C_{drag} \, \rho_{air} \, \pi \, D^{2} \, V_{T}^{2} /8 \ = \ m \, g

You can easily solve for terminal velocity "VT" in the above equation.

The above value can be checked experimentally by dropping the sphere from an elevated level (tall ladder might do) in still air. Time the fall and divide the distance fallen (e.g., height of the level) by the time interval to determine approx terminal velocity. You'll need to determine experimentally (& with calculations) the drop height needed to obtain reasonably accurate results.


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Last edited:
xanthym said:
The above value can be checked experimentally by dropping the sphere from a tall ladder in still air. Time the fall and divide the distance fallen (e.g., height of the ladder) by the time interval to determine approx terminal velocity.

I presume that you're assuming V_T &lt;&lt; \sqrt{2gh} for that calculation, right? A web search gave a terminal velocity of about 10~ m/s for a ping-pong ball, so your ladder would have to be a good bit greater than 5 meters. Not crazy, but a bit of a stretch for everyday purposes.
 
wow this looks quite complicated. but thanks loads anyway! is there any other method/experiments tt we can use to determine the terminal velocity of the ping pong ball?
 
It's really not that complicated of an equation. We gave you C, your coefficient of drag as 0.44. D the diameter can be easily measured or even just looked up online (simply just the diameter of a ping pong ball). Gravity is known, mass can be measured, and the density of air can be found in charts for given air temperatures. Then, just solve for V. It would be much easier than measuring experimentally, and given the margin for error in the experiment, would probably be more accurate.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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