- #1

shark1818

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## Homework Statement

There is a ping pong ball being lifted and suspended in the air by a hair dryer. A.)What is the upward vertical force needed to suspend the ping pong ball? A ping pong ball has a Mass of about 2 grams. B.)If the pressure underneath and inside the ping pong ball is 1 atm what is the pressure above the ping pong ball in Newtons per square meter and C.)what is the average speed of the air in m/sec.

## Homework Equations

Bernoulli: P+(1/2)ρV^2+mgh= P+(1/2)ρV^2+mgh

P=F/A

## The Attempt at a Solution

For A.) I started with P=F/A and i assumed that the Pressure would be that of 1 Atm and the area of a ping pong ball would be around .005 m^2 based on experience. So the force I got was .005 Newtons. I feel that I am extremely off.

For B and C) I used the bernoulli equation but mixed and matched symbols and somehow got huge numbers. A walk through of how to approach this problem would be greatly appreciated.