Calculating the 2nd Derivative of 3x - xln3 | Homework Help

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SUMMARY

The second derivative of the function f(x) = 3x - x(ln3) is calculated as f''(x) = 3 - 1/3. The initial derivative f'(x) was incorrectly stated as 3x*ln3 - (ln3 + x/3), where the term x/3 was misinterpreted. It is crucial to recognize that ln(3) is a constant, and its derivative is zero, not 1/3. This clarification is essential for accurate differentiation in calculus.

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Homework Statement


What is the 2nd derivative of 3x - x(ln3)?


Homework Equations





The Attempt at a Solution


I got this:
f'(x) = 3x*ln3 -(ln3+x/3)
f''(x) = 3x*ln3*ln3 -1/3 - 1/3
 
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[tex]f'(x) = 3^x \cdot ln3 -(ln3+\frac{x}{3})[/tex]

How did you get the x/3 part? And in your second derivative, are you claiming that [tex]\frac{d}{dx} ln(3) = \frac{1}{3}[/tex]? You need to remember that ln(3) is a constant.
 

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