Calculating the Antiderivative of (-4x)/(x^2 + 3) dx

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Homework Help Overview

The discussion revolves around finding the antiderivative of the function (-4x)/(x^2 + 3) dx, which falls under the subject area of calculus, specifically integration techniques.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to find the antiderivative and presents an answer of -2 + c, prompting others to question the validity of this result. Participants inquire about the steps taken to arrive at that answer and suggest the need for more detailed work to identify any mistakes. A hint regarding a specific integration technique involving the form f'(x)/f(x) is also provided.

Discussion Status

The discussion is ongoing, with participants actively engaging in clarifying concepts and exploring different approaches to the problem. Some guidance has been offered regarding the need to show work for better assistance, and a specific technique for integration has been suggested.

Contextual Notes

There is an emphasis on the need for the original poster to provide more detail about their thought process and calculations, as well as a reminder that the term "antiderivative" is synonymous with "indefinite integral."

rayray19
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Homework Statement




the antiderivative of (-4x)/(x^2 + 3) dx





Homework Equations





The Attempt at a Solution



i got -2+c is that right at all, if not can somebody help me
 
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If your answer is:

-2 + c

Then no, not even in the ballpark.

Please explain what you did to arrive there.

Note "antiderivative" is the same as "indefinite integral".

To check your answer, take the derivative. If you arrive at the question, you have the right answer.

(Unless of course you had a definite integral, in which case -2 + c could be correct after evaluating the integral on its parameters.)
 
Here's a hint to get you going:

There's a special technique of integration if you want to find integral of f'(x)/f(x). Note that you can easily express the integral in that form.
 
rayray; please note that you must start showing some work here in order for us to help you. Simply quoting an answer does not show what effort you have made, or even what you have done to get your answer. In this question for example, I have no idea what you have done to get your answer; but if you showed your work, I would probably be able to point out your mistakes.

As for the actual approach; I would take Defennnder's advice and try to recall how to integrate f'/f.
 

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