Calculating the Average of 2 Functions

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SUMMARY

The discussion focuses on calculating the average of two functions over a specified time period. The first function, defined as \(1 - e^{-t/1ms}\), applies from 0 to 5 milliseconds, while the second function, \(e^{-t/1ms}\), applies from 5 to 10 milliseconds. The correct average is determined to be \(\bar{f} = \frac{1}{10}\int^{5ms}_{0}{1-e^{-t/1ms}}dt + \frac{1}{10}\int^{5ms}_{0}{e^{-t/1ms}}dt\), ensuring that both functions contribute equally to the overall average over the 10-millisecond period.

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dimpledur
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Homework Statement


My question pertains to taking the average over a particular period that is composed of 2 functions. For example, from [0, 5ms] the function is defined by 1-e^(-t/1ms)and then by e^(-t/1ms) from [5ms, 10ms].

Will the average from 0-->10 simply be the following:
\bar{f}=\frac{1}{5}\int^{5 ms}_{0}{1-e^{-t/1 ms}}+\frac{1}{5}\int ^{5}_{0}{e^{-t/1 ms}}
 
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If you look at the bottom graph that is orange, it gives visual representation as to what I am trying to take the average of. One period, two functions. One function for half the period, another function for the last half.
1873_8RC%20Input%20Waveform.JPG
 
Nvm, pretty sure it is as follows:
\bar{f}=\frac{1}{10}\int^{5 ms}_{0}{1-e^{-t/1 ms}}+\frac{1}{10}\int ^{5}_{0}{e^{-t/1 ms}}
Since the entire period is 10, then both contributions from each function needs to be divided by this number. If I hadn't done this, I would not be considering the other half where each function is zero.
 

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