Calculating the capacitance of a parallel-plate air capacitor

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SUMMARY

The capacitance of a parallel-plate air capacitor with plates measuring 18 cm on each side and spaced 3.5 mm apart, connected to a 3-V battery, is calculated using the formula C = εo(A/d). The correct area A is determined to be 0.0324 m², leading to a capacitance of approximately 9.44e-11 F. The initial misunderstanding stemmed from interpreting "18 cm square" incorrectly as 18 cm² instead of a square with 18 cm sides.

PREREQUISITES
  • Understanding of capacitance and its formula C = εo(A/d)
  • Familiarity with the concept of parallel-plate capacitors
  • Knowledge of SI units and unit conversions
  • Basic understanding of electric fields and dielectric materials
NEXT STEPS
  • Study the derivation and applications of the capacitance formula C = εo(A/d)
  • Explore different types of capacitors and their characteristics
  • Learn about the effects of dielectric materials on capacitance
  • Investigate practical applications of capacitors in electronic circuits
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Students in physics or electrical engineering, educators teaching capacitor concepts, and anyone interested in understanding the fundamentals of capacitance and its calculations.

shandsy
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Homework Statement


A parallel-plate air capacitor is made by using two plates 18 cm square, spaced 3.5 mm apart. It is connected to a 3-V battery.

What is the capacitance?


Homework Equations



C = εo(A/d)



The Attempt at a Solution



εo = 8.854e-12
A = .18 m
d = .0035 m

C = εo (.18/.0035) = 4.55348571e-10 F

This is coming up as the wrong answer. I have no idea what I'm doing wrong.
 
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Never mind, I solved the problem. I read "18 cm square" to mean 18 cm2, but I guess it really meant a square with 18cm sides, so A = .0324 m2. Sorry about that!
 

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