Capacitance Formula for Parallel Plate Capacitor with Dielectric Material?

In summary, the conversation discusses finding the capacitance of a parallel plate capacitor with half of the space between the plates filled with a dielectric material. The formula for capacitance is derived using the area and distance between the plates, as well as the dielectric constant κ and the permittivity of free space ε0. The final equation for capacitance as a function of L is (ε0*L^2/2s)(1 + κ ). The only mistake in the solution was a typo in the second equation, which was corrected in the following equations.
  • #1
yjk91
75
0

Homework Statement


A capacitor has parallel plates, with half of the space between the plates filled with a dielectric material of constant κ and the other half filled with air as shown in the figure. Assume that the plates are square, with sides of length L, and that the separation between the plates is s. Determine the capacitance as a function of L. (Use any variable or symbol stated above along with the following as necessary: ε0.)

http://www.webassign.net/bauerphys1/24-p-050.gif

The Attempt at a Solution




From the figure, there are two capasitors in parallel circuit.
C = C1 + C2
= εo * A/d + εo * A/d
= εo * 0.5L*L/s + Kεo * 0.5L * L/s
= (εo * 0.5L^2/s)(1 + κ )
--> C = (εo*L^2/2s)(1 + κ )


mm where did i got wrong?
 
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  • #2
yjk91 said:

Homework Statement


A capacitor has parallel plates, with half of the space between the plates filled with a dielectric material of constant κ and the other half filled with air as shown in the figure. Assume that the plates are square, with sides of length L, and that the separation between the plates is s. Determine the capacitance as a function of L. (Use any variable or symbol stated above along with the following as necessary: ε0.)

http://www.webassign.net/bauerphys1/24-p-050.gif

The Attempt at a Solution




From the figure, there are two capasitors in parallel circuit.
C = C1 + C2
= εo * A/d + εo * A/d
= εo * 0.5L*L/s + Kεo * 0.5L * L/s
= (εo * 0.5L^2/s)(1 + κ )
--> C = (εo*L^2/2s)(1 + κ )


mm where did i got wrong?

The answer looks correct to me. There is a typo in your 2nd equation, where you should either have the terms be just ε, or the 2nd term should be Kεo, but you correct that in the 3rd equation, and the rest looks okay. It gives the correct answer when K=1, for example.
 

Related to Capacitance Formula for Parallel Plate Capacitor with Dielectric Material?

1. What is the basic formula for calculating capacitance?

The basic formula for calculating capacitance is C = Q/V, where C is capacitance in farads (F), Q is charge in coulombs (C), and V is voltage in volts (V).

2. How do I calculate the capacitance of a parallel plate capacitor?

The capacitance of a parallel plate capacitor can be calculated using the formula C = εA/d, where C is capacitance in farads (F), ε is the permittivity of the material between the plates, A is the area of the plates, and d is the distance between the plates.

3. What is the formula for calculating the energy stored in a capacitor?

The formula for calculating the energy stored in a capacitor is E = 1/2CV^2, where E is energy in joules (J), C is capacitance in farads (F), and V is voltage in volts (V).

4. How do I determine the capacitance of a cylindrical capacitor?

The capacitance of a cylindrical capacitor can be calculated using the formula C = 2πεl/ln(b/a), where C is capacitance in farads (F), ε is the permittivity of the material between the cylinders, l is the length of the cylinders, b is the outer radius, and a is the inner radius.

5. Is there a formula for calculating the capacitance of a non-parallel plate capacitor?

Yes, there is a general formula for calculating the capacitance of a non-parallel plate capacitor, which is C = Q/V, where C is capacitance in farads (F), Q is charge in coulombs (C), and V is the potential difference between the two plates.

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