(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

If an uncharged parallel-plate capacitor (capacitance C) is connected to a battery, one plate becomes negatively charged as electrons move to the plate face (area A). The depth d from which the electrons come in the plate in a particular capacitor is plotted against a range of values for the potential difference V of the battery. When d is one picometre, the potential difference is 20V. The gradient is equal to 5x10^{-14}. What is the ratio C/A.

2. Relevant equations

q=ε₀EA

q=CV

3. The attempt at a solution

I combined the above two equations to get the expressions C/A=ε₀/D

However that doesn't provide me with a numerical solution for the ratio C/A.

Can anyone please help?

**Physics Forums | Science Articles, Homework Help, Discussion**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Homework Help: Calculating the capacitance problem

**Physics Forums | Science Articles, Homework Help, Discussion**