Calculating the capacitance problem

  • Thread starter Thread starter ctpengage
  • Start date Start date
  • Tags Tags
    Capacitance
Click For Summary
SUMMARY

The discussion centers on calculating the ratio of capacitance to area (C/A) for an uncharged parallel-plate capacitor connected to a battery. The problem states that when the depth (d) from which electrons originate is one picometre, the potential difference (V) is 20V, with a gradient of 5x10-14. The user attempts to derive the ratio using the equations q=ε₀EA and q=CV, ultimately finding that C/A=ε₀/D, but struggles to interpret the meaning of the gradient and its units.

PREREQUISITES
  • Understanding of capacitor fundamentals, specifically parallel-plate capacitors.
  • Familiarity with the equations governing capacitance, including q=ε₀EA and q=CV.
  • Knowledge of electrical potential difference and its relationship to charge and capacitance.
  • Basic grasp of gradients in mathematical contexts, particularly in physics.
NEXT STEPS
  • Research the physical significance of the gradient in capacitor charge distribution.
  • Explore the relationship between capacitance, area, and distance in parallel-plate capacitors.
  • Study the implications of ε₀ (the permittivity of free space) in capacitor calculations.
  • Investigate the units of measurement for potential difference and their relevance in electrical equations.
USEFUL FOR

Students studying electrical engineering, physics enthusiasts, and anyone seeking to understand capacitor behavior in circuits.

ctpengage
Messages
33
Reaction score
0

Homework Statement


If an uncharged parallel-plate capacitor (capacitance C) is connected to a battery, one plate becomes negatively charged as electrons move to the plate face (area A). The depth d from which the electrons come in the plate in a particular capacitor is plotted against a range of values for the potential difference V of the battery. When d is one picometre, the potential difference is 20V. The gradient is equal to 5x10-14. What is the ratio C/A.

Homework Equations



q=ε₀EA
q=CV

The Attempt at a Solution



I combined the above two equations to get the expressions C/A=ε₀/D
However that doesn't provide me with a numerical solution for the ratio C/A.

Can anyone please help?
 
Physics news on Phys.org
I don't understand what is meant by "the depth ... from which the electrons come in the plate".

Also, what is this "gradient equal to 5x10-14" mean? And what are the units?
 

Similar threads

  • · Replies 16 ·
Replies
16
Views
2K
Replies
5
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 28 ·
Replies
28
Views
3K
Replies
4
Views
1K
Replies
3
Views
2K
Replies
2
Views
2K
Replies
10
Views
5K