Equivalent Capacitance of Five Plates with Uniform Area and Spacing

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Homework Statement


Five plates with same area are placed as in figure. Distance between any 2 consecutive plates is d. Find equivalent capacitance(ab). (Note-Answer is given as 5C/3, in terms of C so I suppose C is capacitance of a +ve and -ve plate separated by d). The lower letter is A, it is marked positive and upper letter is B marked negative.

Homework Equations


All related.

The Attempt at a Solution


numbering 1 to 5 from top to bottom. I can see 1 capacitor due to negative 2 and positive 3 and none else since 1 and 4 are uncharged so answer should be C...unless charges get induced. In that case there are 4 capacitors and answer should be 4C. I'd be grateful for some help.
 

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Your picture is not clear. Please post another one.
 
e-pie said:
Your picture is not clear. Please post another one.
I only have a inbuilt webcam...please pardon the poor quality. I'll post another one however, I've provided all information and the general outline of the figure should be enough...
 

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Try drawing an equivalent circuit. It should have four capacitors on it, one per gap.

The top plate and forth plate are connected together. I recommend labeling that connection node C.
 
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CWatters said:
Try drawing an equivalent circuit. It should have four capacitors on it, one per gap.

The top plate and forth plate are connected together. I recommend labeling that connection node C.
Got it! That was very neat. Thank you very much for your help.
 

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