Calculating the Center of Mass for a CO Molecule

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Homework Help Overview

The discussion revolves around calculating the center of mass (CM) for a carbon monoxide (CO) molecule, specifically focusing on the positions of the carbon and oxygen atoms and their respective masses.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to apply the center of mass formula but expresses confusion regarding the positions of the atoms. Some participants clarify that the variables in the formula represent the positions rather than the radii of the atoms.

Discussion Status

The discussion has progressed with participants providing guidance on how to define a coordinate system for the atoms. The original poster indicates they have successfully calculated the center of mass after understanding the positioning, and they seek further assistance on additional problems.

Contextual Notes

There is a mention of a lack of explicit information regarding the positions of the atoms, but the distance between them is provided. The original poster initially struggles with the setup of the problem.

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The distance between a carbon atom (m = 12.0u) and an oxygen atom (m = 16.0u) in the CO molecule is 1.13×10-10 m. How far from the carbon atom is the center of mass of the molecule?

I know i have to found out the CM,

but the center of mas is cm= (r1m1 + r2m2)/(m1+m2)

and i don't have the radios of the twoatoms... how could i do that?
 
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Look up your cm formula. The r1 and r2 are not the radii of the atoms. What are they?
 
ok, i mean the position of the atoms, but there the exercise doesn't told me the psoition...
 
It told you the distance between the atoms. Put the origin of your coordinate system anywhere you want. Write down the position of the atoms in that coordinate system and find the coordinate of the center of mass. Then figure out how far it is from the carbon atom.
 
ty... i figure out the coordinates system in the origin of one atom and calculate the CM since that point an gets the corrects anwer... ty a lot... can u help me with other problems a posted in a new topic?..
 
Sure. Maybe not tonite. It's late. Other people can help you too.
 

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