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- Thread starter morechem28
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- #71

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- #72

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Thank you. And as doing so, will the sum: p (atm) + p (hydr) be the right substituent for p?

- #73

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And what is p(hydr) equal to?

- #74

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- #75

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I have to quit now and tend to other business. See how far you can go.

- #76

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Thank you, I really appreciate your help!

- #77

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- #78

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- #79

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That's not what I get. I get about 30 MPa = 300 Bars. Let's see your arithmetic and your management of units.

- #80

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My answer agrees with @Chestermiller's answer.That's not what I get. I get about 30 MPa = 300 Bars. Let's see your arithmetic and your management of units.

- #81

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Thank you, yes. I should divide (density*R*T) by 0,0838 kg/mol, not 83,8 g/mol. Now, I get 30.76 (p (cr)) MPa. And now, I'd do this: p(cr) - p(atm) = p(hydr), p(hydr) = 30 763 387.4 - 101 325 = 30 662 062.4 Pa. And then, given that: p (hydr) = density*h*g; h = p (hydr)/(density*g) = 3005.38 m. Is that right, please?My answer agrees with @Chestermiller's answer.

- #82

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Do you really feel that 6 significant figures is justified for this calculation? What would your answer be for a realistic number of significant figures?Thank you, yes. I should divide (density*R*T) by 0,0838 kg/mol, not 83,8 g/mol. Now, I get 30.76 (p (cr)) MPa. And now, I'd do this: p(cr) - p(atm) = p(hydr), p(hydr) = 30 763 387.4 - 101 325 = 30 662 062.4 Pa. And then, given that: p (hydr) = density*h*g; h = p (hydr)/(density*g) = 3005.38 m. Is that right, please?

What is the critical pressure of Krypton? Based on this, do you feel that use of the ideal gas law was accurate enough for this calculation? How would you modify the calculation to take into account the deviation from ideal gas behavior?

- #83

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Yes, I think I get it. But in accordance with the original assignment, I should consider Kr an ideal gas. I know that is not real, but the whole situation is meant to be hypothetical.Do you really feel that 6 significant figures is justified for this calculation? What would your answer be for a realistic number of significant figures?

What is the critical pressure of Krypton? Based on this, do you feel that use of the ideal gas law was accurate enough for this calculation? How would you modify the calculation to take into account the deviation from ideal gas behavior?

- #84

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@morechem28, note that @Chestermiller asked you some specific questions in Post #82. But you didn’t answer any of them!Yes, I think I get it. But in accordance with the original assignment, I should consider Kr an ideal gas. I know that is not real, but the whole situation is meant to be hypothetical.

If I were replying to him, here’s how I would have answered the first two questions:

No. 3005.38 m has 6 significant which is too many. The depth can’t be determined to the nearest centimetre because the data used in the calculation are not precise enough.Do you really feel that 6 significant figures is justified for this calculation?

Two or three significant figures is realistic, since the values used (see Post #1) are given to only three significant figures (and only multiplications and divisions have been used).What would your answer be for a realistic number of significant figures?

So I should have given my answer as 3.0x10⁴m or 3.01x10⁴m.

- #85

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Okay, thank you for your help. Now I get it.

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