Calculating the Dimensions of a Reinforced Concrete Column Under Stress

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The discussion focuses on calculating the dimensions of a reinforced concrete column under stress, specifically a square section strut. The modulus of elasticity for concrete is 20 GN/m², while for steel, it is 200 GN/m². The maximum allowable stress in the concrete is 7 MN/m², and the total load on the column is 400 kN. The area of the steel reinforcement, calculated using two 25 mm diameter bars, is approximately 0.000981747 m². The final dimensions of the column are derived by ensuring the total area accounts for both the concrete and steel, leading to a required cross-sectional area of approximately 220 mm².

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anthonyk2013
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A concrete column having a modulus of elasticity of 20GN/m2 is reinforced by two steel bars of 25mm diameter having modulus of 200GN/m2.
Calculate the dimensions of a square section strut if the stress in the concrete is not to exceed 7MN/m2 and the load is to be 400KN.

σ in conctete not to exceed 7*106
Load =400KN
E of steel=200GN/m2
E of concrete=20GN/m2

Area of steel=3.14*252/4*2=982*10-3m2
Area of concrete=?

σc/Ecs/Es

σcs*Ec/Es

σcs*20/200

σcs*.1


7*106s*.1

7/.1*106s

σs=70*106MN/M2

Wondering if I m on the right track?
 
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You could indicate the units of your calculations.
 
SteamKing said:
You could indicate the units of your calculations.

Well do. Bad habit
 
Any help would be appreciated
 
anthonyk2013 said:
Any help would be appreciated
Let S be the side of the square cross section column. What is the total area of the cross section. What is the cross sectional area of the steel rods (this time calculate it correctly, taking into account that 1 mm = 0.001 m)? In terms of S, what is the cross sectional area of the concrete?
 
Chestermiller said:
Let S be the side of the square cross section column. What is the total area of the cross section. What is the cross sectional area of the steel rods (this time calculate it correctly, taking into account that 1 mm = 0.001 m)? In terms of S, what is the cross sectional area of the concrete?

Area of the steel is 3.14*.0252/4=.0004908
Because there is two rods I multiply .0004908*2=.000981747m2

S=L*B
 
anthonyk2013 said:
Area of the steel is 3.14*.0252/4=.0004908
Because there is two rods I multiply .0004908*2=.000981747m2

S=L*B

What are L and B?

For the cross sectional area of the concrete, I get (S - 0.000981747) m2.
 
Chestermiller said:
What are L and B? Length x breath

For the cross sectional area of the concrete, I get (S - 0.000981747) m2.

Yes S-0.000981747
 
anthonyk2013 said:
Yes S-0.000981747
Actually, S2-0.000981747. What is your recommendation as to what to do next in this problem?
 
  • #10
I need the get area using the values I have.

do I use σc/Ecs/Es

σcs=Ec/Es

σc=Fc/Ac and σs=Fs/As

THEN Fc/Ac*As/Fs=Ec/Es
 
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  • #11
anthonyk2013 said:
I need the get area using the values I have.

do I use σc/Ecs/Es

σcs=Ec/Es

σc=Fc/Ac and σs=Fs/As

THEN Fc/Ac*Fs/As=Ec/Es
Let ε be the compressive strain in the steel and concrete. What value of ε causes the stress in the concrete to equal 7MN/m2? What is the stress in the bars? In terms of S, what is the compressive force in the bars and in the concrete? What are the sum total of the compressive forces? What value of S causes this total compressive force to equal 400 kN.
 
  • #12
ε of concrete=ε in steel?

σ=E*ε

ε=σ/E ε=7MN/m2/20N/m2

Would the correct way the write this be ε=7*106/20*109=.35*10-3

σ in steel=.35*200=70MN

Total force is 400KN so I need to find what load is on the steel.
 
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  • #13
anthonyk2013 said:
ε of concrete=ε in steel?

σ=E*ε

ε=σ/E ε=7MN/m2/20N/m2

Would the correct way the write this be ε=7*106/20*109=.35*10-3

σ in steel=.35*200=70MN

Total force is 400KN so I need to find what load is on the steel.
So far, so good. Now, you know the stress in the steel. What is the load carried by the two steel bars?
 
  • #14
Chestermiller said:
So far, so good. Now, you know the stress in the steel. What is the load carried by the two steel bars?

σ=F/A→F=σ*A→F=70*106*0.000981747m2=.06872MN/m2

or 69KN/m2
 
  • #15
Total force is 400KN, force in steel is 69KN so 400KN-69KN=331KN

Force in concrete=331KN
σ in concrete=7MN/m2

Area=f/σ A=331*103/7*106=47.285*103 or 47285

\sqrt{}47285=217.45mm2

Answer in my notes is 220mm2
 
  • #16
anthonyk2013 said:
Total force is 400KN, force in steel is 69KN so 400KN-69KN=331KN

Force in concrete=331KN
σ in concrete=7MN/m2

Area=f/σ A=331*103/7*106=47.285*103 or 47285

\sqrt{}47285=217.45mm2

Answer in my notes is 220mm2
You're still not being careful about units. You made two errors that canceled each other out. Incidentally, the length of the side of the square cannot be in mm2. It has to be mm.
 
  • #17
Chestermiller said:
You're still not being careful about units. You made two errors that canceled each other out. Incidentally, the length of the side of the square cannot be in mm2. It has to be mm.

217.45mm is what should have wrote?
 
  • #18
anthonyk2013 said:
217.45mm is what should have wrote?
Not exactly. You had to add the area of the bars back to get the total area. Then take the square root. That's probably why you got 217 and the book had 220.
 
  • #19
To get the dimensions I need to find the total area. Concrete +steel and square root that.

Thanks for your help Chester, big help again.
 

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