Calculating the Distance of a Plane from a Radar Station Using Related Rates

[Weave]

Homework Statement

This last related rates HW problem is givin me trouble for some odd reason.
A plane flying with a constant speed of 4 km/min passes over a ground radar station at an altitude of 11 km and climbs at an angle of 25 degrees. At what rate, in km/min is the distance from the plane to the radar station increasing 1 minutes later?

Homework Equations

Law of Cosines:
c^2=a^2+b^2-2abCos(\theta)
a=11km
b=4km
\frac{da}{dt}=0
\frac{db}{dt}=4km/min

The Attempt at a Solution

First using the law of cosines I found c at that particular moment.
c=\sqrt(137-88Cos(23\pi/36))
Second I found the derivative of the law of cosines
Working everything out I get:
\frac{dc}{dt}=\frac{16-44cos(23\pi/36)+44sin(23\pi/36)}{c}
I plug in c and get the wrong answer, what did I do wrong?

 

[Weave]

c by the way is the hypotnuse, a in the altitude, and b is length the plane travels,

 

[HallsofIvy]

Homework Statement

This last related rates HW problem is givin me trouble for some odd reason.
A plane flying with a constant speed of 4 km/min passes over a ground radar station at an altitude of 11 km and climbs at an angle of 25 degrees. At what rate, in km/min is the distance from the plane to the radar station increasing 1 minutes later?

Homework Equations

Law of Cosines:
c^2=a^2+b^2-2abCos(\theta)
a=11km
b=4km

b is NOT "4km". b is a variable and you are told that db/dt= 4 km/min

\frac{da}{dt}=0
\frac{db}{dt}=4km/min

The Attempt at a Solution

First using the law of cosines I found c at that particular moment.
c=\sqrt(137-88Cos(23\pi/36))
Second I found the derivative of the law of cosines
Working everything out I get:
\frac{dc}{dt}=\frac{16-44cos(23\pi/36)+44sin(23\pi/36)}{c}
I plug in c and get the wrong answer, what did I do wrong?

Also, there is no reason to convert 25 degrees to 23\pi/36 since it is a constant. That doesn't change the result but I thought it was peculiar to convert from degrees to radians (and surprised that it was such a simple result!).

 

[Weave]

Homework Statement

This last related rates HW problem is givin me trouble for some odd reason.
A plane flying with a constant speed of 4 km/min passes over a ground radar station at an altitude of 11 km and climbs at an angle of 25 degrees. At what rate, in km/min is the distance from the plane to the radar station increasing 1 minutes later?

Homework Equations

Law of Cosines:
c^2=a^2+b^2-2abCos(\theta)
a=11km
b=4km

b is NOT "4km". b is a variable and you are told that db/dt= 4 km/min




Also, there is no reason to convert 25 degrees to 23\pi/36 since it is a constant. That doesn't change the result but I thought it was peculiar to convert from degrees to radians (and surprised that it was such a simple result!).

But at that instant isn't b=4km?

 

[HallsofIvy]

Oops! Yes, I skipped over the "1 minute later" part.

However the point is that is not a "constant"- b is changing as time goes on. You cannot evaluate at b= 4 until after you take the derivative.
And how did you get that "sin(23\pi/36)"? You don't differentiate the cosine- its a constant.

The law of cosines tell you that
c^2= 11^2+ b^2- 22b cos(115)
Differentiating that with respect to t gives you
2c dc/dt= 2b db/dt- 22cos(115) db/dt[/itex]<br /> <br /> Now use the fact that, at this instant, b= 4 km, db/dt= 4 km/min. You will need to determine c, at this instant, from the law of cosines.

 

[Weave]

ah! thanks!