Induced Emf in a Rectangular Coil

[member 217843]

Homework Statement

A rectangular coil of 90 turns has dimensions of 22 x 65 cm and is located in a uniform 1 T magnetic field. In 1.7 s, the plane of the coil is rotated from a position where it makes an angle of 19° with the magnetic field to a position where it makes an angle of 64°. Calculate the average emf induced in the coil.

Homework Equations

emf= -N*(d\Phi/dt)
\Phi=BAcos\vartheta

The Attempt at a Solution

So I calculated the change in flux to be: (B*A*cos(90-64))-(B*A*cos(90-19)=B*A*(cos(26)-cos(71))

I then calculated emf.
emf= - ((90 turns)*(1 T)*(0.22m*0.65m)*(cos(26)-cos(71)))/1.7 s = -4.34 V
This is wrong. I then entered the absolute value, which is also incorrect.

 

[tiny-tim]

Hi SgtMousse!

I then calculated emf.
emf= - ((90 turns)*(1 T)*(0.22m*0.65m)*(cos(26)-cos(71)))/1.7 s = -4.34 V
This is wrong. I then entered the absolute value, which is also incorrect.

looks ok

have you tried 4.3 V, since it should be two significant figures ?​

 

[member 217843]

Apparently my answer was correct, even though it was marked wrong. I just checked my online homework site, and they marked it correct. They must have had it wrong before. Thanks anyway!