(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Calculate the energy and radius for each of the five lowest (n = 1,2,3,4,5) electron orbits in a Helium atom with only one electron. Enter the energy as a positive value in units of "eV" and the radius in units of "nm". Hint: The Helium nucleus has 2 protons so Z = 2 and the ground state energy of Helium will be E0 = k(Ze)2/2r0.

2. Relevant equations

E = (E_{0}/n^{2})*Z^{2}

E_{0}= 13.6 eV

Z^{2}=4

r=(r_{0}/Z)*n^{2}

Z=2

3. The attempt at a solution

I got the correct answers for n = 1-2 and 4-5, but I cannot get the right answer for n=3. could you check my work?

The answers I got were E = 6.044 eV and r = .238 nm

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# Homework Help: Calculating the energy level and radius for a helium atom

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