The discussion focuses on calculating the final velocity of a baseball thrown directly upward, which is caught after 3.2 seconds. The acceleration due to gravity is established as -9.8 m/s², and the initial velocity (Vi) is determined using the equation y(t) = y0 + vi * t + (0.5 * ay) * t². The final calculations yield an initial velocity of 31.36 m/s, which is necessary for the ball to return to the thrower's hand after the specified time. The participants emphasize the importance of correctly applying the quadratic equation and understanding the motion equations in projectile motion.
PREREQUISITESStudents studying physics, educators teaching kinematics, and anyone interested in understanding projectile motion and its calculations.
Medgirl314 said:Great, thanks! The equation I used, or a different one?
Medgirl314 said:y(t)=y0+viy∗t+(0.5∗ay)∗t2
y(3.2s)=0+0*3.2+(0.5)(-9.8y)*10.24
y(3.2s)=3.2s+(0.5)(9.8y)*10.24s
Is that right so far? What's next?