Yes, 86.2 N sounds like a more accurate answer. Great job on your solution!

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SUMMARY

The discussion centers on calculating the horizontal force required to accelerate a 15 kg crate at 3.0 m/s², given a coefficient of friction (μ) of 0.28. The initial calculation yielded a force of 81.16 N, but a participant later corrected this to 86.16 N, rounded to 86.2 N, after realizing a mistake in their calculations. The correct formula used was F = ma + μmg, confirming the importance of accurately applying the coefficient of friction in such problems.

PREREQUISITES
  • Understanding of Newton's second law (Fnet = ma)
  • Knowledge of friction coefficients and their application
  • Ability to perform basic algebraic calculations
  • Familiarity with the concept of mass and weight (m and mg)
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  • Review the application of friction in physics problems
  • Learn about different types of friction (static vs. kinetic)
  • Explore advanced dynamics involving multiple forces
  • Practice similar problems using varying coefficients of friction
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Students studying physics, particularly those focusing on mechanics and dynamics, as well as educators looking for examples of force calculations involving friction.

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Homework Statement



A 15 kg crate rests on the floor. The coefficient of friction between the crate and the floor is 0.28. How much horizontal force is needed to accelerate the crate at 3.0 m/s^2?


Homework Equations



Fnet=ma

The Attempt at a Solution


m=15 kg
F-f=ma
F-MN=ma
F-Mmg=ma
F=ma+Mmg
F=15*3+.38*15*9.8
F=81.16 N.
For a final rounded answer of: F=81.2 N.

This answer seems correct to me, could someone please confirm?

Thanks! :smile:
 
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Medgirl314 said:

Homework Statement



A 15 kg crate rests on the floor. The coefficient of friction between the crate and the floor is 0.28. How much horizontal force is needed to accelerate the crate at 3.0 m/s^2?


Homework Equations



Fnet=ma

The Attempt at a Solution


m=15 kg
F-f=ma
F-MN=ma
F-Mmg=ma
F=ma+Mmg
F=15*3+.38*15*9.8 (0.28 is the μ in the prob. statement)
F=81.16 N.
For a final rounded answer of: F=81.2 N.

This answer seems correct to me, could someone please confirm?

Thanks! :smile:

I don't get your result, even with μ = 0.28. Try your calculator again.
 
Oops, I thought I corrected that, sorry! Weird, I somehow mixed up the digits. Does 86.16, rounded to 86.2, sound better?

Thanks!
 

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