Calculating the Force Needed to Lift a 700 lb Car with a Hydraulic Jack

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SUMMARY

The discussion focuses on calculating the force required to lift a 700 lb car using a hydraulic jack with a smaller piston diameter of 0.75 cm and a larger piston diameter of 6.0 cm. By applying Pascal's principle, the force exerted on the smaller piston can be determined using the formula F1/A1 = F2/A2, where F1 is the force applied, A1 is the area of the smaller piston, F2 is the weight of the car, and A2 is the area of the larger piston. The calculated force needed to lift the car is approximately 12.25 lb, demonstrating the mechanical advantage provided by the hydraulic system.

PREREQUISITES
  • Understanding of Pascal's principle in hydraulics
  • Basic knowledge of area calculation for circles
  • Familiarity with force and pressure concepts
  • Ability to perform unit conversions (e.g., pounds to force)
NEXT STEPS
  • Research hydraulic systems and their applications in mechanical engineering
  • Learn about the calculation of areas for circular pistons
  • Explore advanced hydraulic formulas and their implications in lifting mechanisms
  • Study real-world applications of hydraulic jacks in automotive repair
USEFUL FOR

Engineers, automotive technicians, physics students, and anyone interested in understanding hydraulic mechanics and force calculations in lifting systems.

designer rose
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1.A man has a hydraulic jack to lift his car. If the smaller piston has a diameter of .75 cm, and the larger piston a diameter of 6.0 cm, how much force will the man have to exert to lift one corner of the car, weighing 700 lb?
 
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