Calculating the Force of a Planet Using Energy and Radius

[Sanev]

I want to ask if we now the energy of a planet (mc2) and we divided that energy over the radius(R) of that planet what kind of force(F) we get --> mc2/Radius = F(?)

 

[mfb]

That quantity has the same unit as a force, but it is not a force anywhere, and it has no relevance.

If you multiply it by a few fundamental constants you get the ratio of the object’s radius to its Schwarzschild radius (if it would be a black hole). If that ratio is smaller than 1 then you don’t have a planet, you have a black hole.

 

[Sanev]

I'm sorry but i don't understand this IT HAS NO RELEVANCE. Why it doesn't have? Can you explain a little bit more. Thank you!

 

[mfb]

Multiply the width of your thumb by the number of days in a year and divide it by the duration of your last breakfast. The result has the units of a speed. Do you expect the result to have any relevance? Why not?

 

[robphy]

possibly interesting: https://en.wikipedia.org/wiki/Classical_electron_radius

 

[Sanev]

I get it :D thank you for your answer :)