- #1

BrettF

- 5

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A bicycle wheel has a radius R = 32.0 cm and a mass M = 1.82 kg which you may assume to be concentrated on the outside radius. A resistive force

*f =*137 N (due to the ground) is applied to the rim of the tire. A force F is applied to the sprocket at radius

*r*such that the wheel has an angular acceleration of 4.50 rad/s^2. The tire does not slip.

a. If the sprocket radius is 4.53 cm, what is the force, F (in Newtons)?

b. If the sprocket radius is 2.88 cm, what is the force, F?

c. What is the combined mass (kg) of the bicycle and rider?

I know that the tangential acceleration a = rα where α is rotational acceleration.

I also know the Kinetic energy must be

**K = ½ Iω^2+ ½Mv^2**where the first term is the rotational kinetic energy and the second term is the translational kinetic energy.

Finally, I know that

**I**which is the moment of inertia for a shell (the shape of the bicycle) is Mass*Radius^2.

I've been doing the algebra with it and can't seem to get any meaningful results. Am I on the right track with this thinking? Thanks in advance for the help.