Calculating the Fourier Transform of f(x) = 1 if -1<x<1, f(x) = 0 otherwise

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SUMMARY

The Fourier transform of the function f(x) = 1 for -1 < x < 1 and f(x) = 0 otherwise is calculated as \(\hat{f}(w) = \sqrt{\frac{2}{\pi}} \frac{\sin(w)}{w}\). A discrepancy arises with the textbook's answer, which states it should be \(\sqrt{\frac{\pi}{2}} \frac{\sin(w)}{w}\). The calculations provided in the forum discussion confirm the user's solution as correct, indicating that the textbook may contain an error.

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Homework Statement



Find the Fourier transform of the function f(x) = 1 if -1<x<1, f(x) = 0 otherwise

2. The attempt at a solution

[tex]\hat{f}(w) = \frac{1}{\sqrt{2 \pi}} \int ^{1}_{-1}e^{-iwx}dx = \frac{1}{\sqrt{2 \pi}} [\frac{e^{-iwx}}{-iw}]^{1}_{-1} = \frac{1}{-iw \sqrt{2 \pi}}(e^{-iw} - e{iw}) = \sqrt{\frac{2}{\pi}} \frac{sinw}{w}[/tex]

According to my book, the correct answer is [tex]\sqrt{\frac{\pi}{2}} \frac{sinw}{w}[/tex]

Who is right?
 
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I can't find any mistakes in your solution.
 

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