Calculating the heat loss of an open water tank (aquarium)

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SUMMARY

This discussion focuses on calculating heat loss in open water tanks, specifically aquariums, using heat transfer equations. The participants explore conductive heat transfer using Fourier's law and the overall heat transfer coefficient (U), as well as convection heat transfer through Newton's Law of Cooling. Key scenarios include heat loss in winter when water is warmer than air and heat gain in summer when water is cooler than air. The impact of evaporation on heat transfer is also highlighted, emphasizing its dependence on factors like air humidity and surface area.

PREREQUISITES
  • Understanding of heat transfer principles, including conduction, convection, and radiation.
  • Familiarity with Fourier's law and Newton's Law of Cooling.
  • Knowledge of overall heat transfer coefficient (U) and its calculation.
  • Basic concepts of evaporation and its effects on temperature regulation in aquatic environments.
NEXT STEPS
  • Research the calculation of overall heat transfer coefficients for different fluid combinations.
  • Learn about advanced evaporation modeling techniques in varying environmental conditions.
  • Explore empirical equations for evaporation rates under different wind speeds and humidity levels.
  • Investigate the effects of surface area and temperature gradients on heat transfer in aquariums.
USEFUL FOR

Aquarium enthusiasts, environmental engineers, and anyone involved in thermal management of aquatic systems will benefit from this discussion.

Apgomes3
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Hi,

I have been calculating a series of hypothesis for some aquariums/tanks situations, using heat transfer equations (conduction, convection, radiation, evaporation)

Typically we have aquariums that run at higher temperatures than the surroundings in winter and lower temperature than the surroundings at summer ... I stumble into a silly question in trying to establish the scenario

Question 1 is about Conductive heat transfer


When the conduction is in a horizontal plane between two different fluids ( in this case air and water) instead of using Fourier's law

Q= K.A (ΔT/L)

should I do it

Q = = U A dT where U , overall heat transfer coefficient (W/(m2K), captures the individual fluid (air and water) convection heat transfer coefficient

1 / U = 1 / hci + Σ (sn / kn) + 1 / hco Is this a correct way of thinking ? Because the following 2 scenarios then will be more accurate ?
A. When in winter - water is higher in temperature than surrounding air, the heat transfer goes from the inside of the tank towards the surroundings - so I consider a loss of heat.

B. When in summer - water is lower in temperature than surrounding air, the heat transfer goes from the surroundings to the water inside - so I consider a gain in heat.

Question 2 is about Convection heat transfer

Does the same principle above applies to the rationale ? So using Newton's Law of Cooling

Q = = Hc A dT, where dT is temperature difference between the surface and the bulk fluidI won't go into the details of calculating Hc_water (which is a all new thread...!) but my silly questions remains the same:

A. When in winter - water is higher in temperature than surrounding air:

so I consider the hot plane to be the superficial water film layer and the heat transfer is done from this layer to the surrounding air. I use here Hc_water ( convective heat coefficient of water). I consider a loss of heat ( regarding the aquarium)

B. When in summer - water is lower in temperature than surrounding air:

so I consider the hot plane to be the superficial air film layer and the heat transfer is done from this layer to water. I use here Hc_air ( convective heat coefficient of air). I consider a heat gain ( regarding the aquarium)This is not looking as correct to me ... but I couldn't get my head around to be more accurate would greatly appreciate inputs and ideasFor now I am only considering the convective heat transfer in the open top of the aquarium.
 
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The main reason why the water cools is evaporation from the surface.
Evaporation is endothermic.
I think you should look into that.
Obviously the rate of evaporation depends on several things such as air humidity, whether there's a draft or not, size of the surface, temperature of water etc.
 
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Hi @Philip Koeck yes that is true; i am looking or trying to look past it as well so to compute in the losses or gain by conduction, convection and radiation and their role. I have all of that computed now. Evaporation is not linear to calculate in indoor situations when the surface is not calm but also found a good article detailing this known equations and their deviations so its at least a starting point. Typical evaporation is derived from an empirical equation that is accurate enough but for wind speeds above 2 m/s outdoor; indoor hvac is more around 0.15 m/s per some notes.

I do think it is an interesting exercise and sometimes i do need to challenge my logic so to say if i am following a coerent one!

Thank you for your input! Greatly appreciated
 
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