Calculating the Height of a Cliff Using the Speed of Sound

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To calculate the height of a cliff from which a rock is dropped, the total time of 3.7 seconds includes both the time it takes for the rock to fall and the time for the sound to travel back up. The speed of sound is given as 340 m/s, and the equations for distance and time must be used correctly to find the height. The relationship between the time for the rock to fall and the time for sound to travel back is crucial for solving the problem. The initial velocity of the rock is zero, simplifying the calculations. Clarification on the use of the quadratic equation and the correct application of the equations is needed for a complete solution.
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Homework Statement



A rock is dropped from a sea cliff, and the sound of it striking the ocean is heard 3.7s later. If the speed of sound is 340m.s how high is cliff?

Homework Equations



Ttotal=trock+tsound distance=Vsound*tsound ts=340m/s-trock x=x+vt+.5at^2 quadratic equation

The Attempt at a Solution



did each of these equations to get d=340m/s(3.7- 3.92) its wrong! PLEASE help :(
 
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afa said:
Ttotal=trock+tsound distance=Vsound*tsound ts=340m/s-trock x=x+vt+.5at^2 quadratic equation

ts=d/340m/s

initial v is zero (simplify)
trock = SQRT (2d/g)
 
I don't understand, what are you doing with the second equation?? can you go through the steps?
 

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