Calculating the Height of a Cliff Using the Speed of Sound

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SUMMARY

The problem involves calculating the height of a cliff based on the time it takes for a rock to fall and the sound of it hitting the ocean to travel back. The total time of 3.7 seconds is the sum of the time taken for the rock to fall (trock) and the time taken for the sound to travel back up (tsound). Using the speed of sound at 340 m/s, the equations Ttotal = trock + tsound and distance = Vsound * tsound are essential for solving the problem. The correct approach involves substituting the equations to find the height of the cliff accurately.

PREREQUISITES
  • Understanding of kinematic equations, specifically x = x0 + vt + 0.5at²
  • Knowledge of the speed of sound in air (340 m/s)
  • Familiarity with solving quadratic equations
  • Basic principles of free fall and gravitational acceleration (g = 9.81 m/s²)
NEXT STEPS
  • Learn how to apply kinematic equations to free fall problems
  • Study the derivation and application of the quadratic formula
  • Explore the relationship between time, distance, and speed in sound propagation
  • Practice similar physics problems involving sound and motion
USEFUL FOR

Students studying physics, educators teaching kinematics, and anyone interested in solving real-world problems involving motion and sound.

afa
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Homework Statement



A rock is dropped from a sea cliff, and the sound of it striking the ocean is heard 3.7s later. If the speed of sound is 340m.s how high is cliff?

Homework Equations



Ttotal=trock+tsound distance=Vsound*tsound ts=340m/s-trock x=x+vt+.5at^2 quadratic equation

The Attempt at a Solution



did each of these equations to get d=340m/s(3.7- 3.92) its wrong! PLEASE help :(
 
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afa said:
Ttotal=trock+tsound distance=Vsound*tsound ts=340m/s-trock x=x+vt+.5at^2 quadratic equation

ts=d/340m/s

initial v is zero (simplify)
trock = SQRT (2d/g)
 
I don't understand, what are you doing with the second equation?? can you go through the steps?
 

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