Calculating the highest point of a trajectory

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To calculate the highest point of a soccer ball's trajectory, the initial velocity is 20 m/s at a 20-degree angle. The vertical component of the velocity can be determined using trigonometric functions, specifically by multiplying the initial velocity by the sine of the angle. The only force acting on the ball in the vertical direction is gravity, which accelerates it downward at 9.81 m/s². Using the equations of motion under uniform acceleration, the maximum height can be calculated by determining the time to reach the peak and substituting it back into the vertical motion equation. The discussion emphasizes the importance of focusing solely on the vertical component of motion to find the maximum height.
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1. A soccer ball is kicked with an initial actual velocity of 20 ms at an angle of 20 degrees with the horizontal. Find the vertical distance from ground to highest point.
 
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Take ground as x-axis and perpendicular as y axis. There is no acceleration in x direction.As acceleration in y-axis is gravity, and only y component of velocity is responsible for max height just use basic equations of motion under uniform acceleration and find out the answer.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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