Calculating the integral of x^n e^(2x) from 0 to 1

[ultima9999]

Hey, I got a couple of problems on integration that I can't seem to figure out.

1. Suppose I_n = \int_{0}^{1} x^n e^{2x} dx Evaluate I_n in terms of I_{n-1} for any natural number n


2. Suppose I_n = \int_{1}^{e} \left[\ln x\right]^n dx Evaluate I_n in terms of I_{n-1} for any natural number n

Not sure what to do with these. Do I need to integrate I_{n-1}? What do I put into I_n after I integrate I_{n-1}??

 

[TD]

With

I_n = \int_{0}^{1} x^n e^{2x} dx

then

I_{n-1} = \int_{0}^{1} x^{n-1} e^{2x} dx

Use integration by parts to get a relation between I_n and I_n-1.

 

[ultima9999]

Yup, I did that and I got I_n = \frac{1}{2}x^ne^{2x} - \frac{n}{2}I_{n-1}

For the second question, I let u = ln x, but what would I let dv/dx equal to?

 

[TD]

It's a bit unclear to me what you mean with dv/dx, but do you mean identifying the factors for integration by parts?

Remember that one can integrate ln(x)dx by looking at it as ln(x).1dx and taking u = ln(x) and v = 1, dv = dx.

 

[ultima9999]

Yup! I_n = x[\ln x]^n - nI_{n-1}