Calculating the Limit of {(e^h-1)/h} as h→0

Thread starter Ravi Mandavi
Start date Mar 25, 2012
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To calculate the limit of (e^h - 1)/h as h approaches 0, one effective method is to apply L'Hôpital's Rule, which is useful for resolving indeterminate forms. By differentiating the numerator and denominator, the limit simplifies to e^h as h approaches 0. Evaluating e^h at h = 0 gives a result of 1. This confirms that the limit of (e^h - 1)/h as h approaches 0 is indeed 1. Understanding this limit is crucial in calculus and helps illustrate the derivative of the exponential function at zero.

Mar 25, 2012

Ravi Mandavi

how, limit h->0 {(e^h-1)/h}= 1?
Although this is not home work but i stuck on it

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Mar 25, 2012

rock.freak667

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You can apply L'Hopital's Rule and it should work out.

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