Ravi Mandavi
- 36
- 0
how, limit h->0 {(e^h-1)/h}= 1?
Although this is not home work but i stuck on it
Although this is not home work but i stuck on it
The limit of the expression {(e^h-1)/h} as h approaches 0 is definitively calculated to be 1. This conclusion is reached by applying L'Hôpital's Rule, which is a method used to evaluate limits of indeterminate forms. The application of this rule simplifies the calculation and confirms the limit's value. Understanding this limit is essential for grasping fundamental concepts in calculus, particularly in the context of exponential functions.
PREREQUISITESStudents and educators in mathematics, particularly those focused on calculus, as well as anyone looking to strengthen their understanding of limits and exponential functions.