Calculating the limits without the L'Hospital rule

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mathmari
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Hey! :o

How could we calculate the following limits without the L'Hospital rule?

$$\lim_{x\rightarrow 0}\frac{\sin (x)-x+x^3}{x^3} \\ \lim_{x\rightarrow 0}\frac{e^x-\sin (x)-1}{x^2}$$

Is the only way using the Taylor expansion? (Wondering)
 
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mathmari said:
Hey! :o

How could we calculate the following limits without the L'Hospital rule?

$$\lim_{x\rightarrow 0}\frac{\sin (x)-x+x^3}{x^3} \\ \lim_{x\rightarrow 0}\frac{e^x-\sin (x)-1}{x^2}$$

Is the only way using the Taylor expansion? (Wondering)
It certainly looks as though they are expecting you to use the Taylor series expansions for the sine and exponential functions.
 
Ah ok... Couldn't we use for example the squeeze theorem? (Wondering)
 

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