Calculating the limits without the L'Hospital rule

  • Context:
  • Thread starter Thread starter mathmari
  • Start date Start date
  • Tags Tags
    Limits
Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
2 replies · 2K views
mathmari
Gold Member
MHB
Messages
4,984
Reaction score
7
Hey! :o

How could we calculate the following limits without the L'Hospital rule?

$$\lim_{x\rightarrow 0}\frac{\sin (x)-x+x^3}{x^3} \\ \lim_{x\rightarrow 0}\frac{e^x-\sin (x)-1}{x^2}$$

Is the only way using the Taylor expansion? (Wondering)
 
Last edited by a moderator:
Physics news on Phys.org
mathmari said:
Hey! :o

How could we calculate the following limits without the L'Hospital rule?

$$\lim_{x\rightarrow 0}\frac{\sin (x)-x+x^3}{x^3} \\ \lim_{x\rightarrow 0}\frac{e^x-\sin (x)-1}{x^2}$$

Is the only way using the Taylor expansion? (Wondering)
It certainly looks as though they are expecting you to use the Taylor series expansions for the sine and exponential functions.
 
Ah ok... Couldn't we use for example the squeeze theorem? (Wondering)