Calculating the Mass Defect of 40Ca

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SUMMARY

The mass defect of the 40Ca nucleus is calculated using the formula Δm=(Zmp+(A-Z)mn)-m, where Z is the atomic number, A is the mass number, mp is the mass of a proton, mn is the mass of a neutron, and m is the actual mass of the nucleus. The initial calculation yielded a mass defect of 0.242 amu, but the correct mass defect is 0.367 amu. The discrepancy was resolved by adjusting the formula to Δm=(Zmp+(A-Z)mn)-(m-Zme), where Zme accounts for the binding energy correction.

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Homework Statement



What is the mass defect of the 40Ca nucleus?

Homework Equations



Δm=(Zmp+(A-Z)mn)-m

The Attempt at a Solution



mass of 40Ca=40.078 amu
mass of proton in amu is mp=1.0073 amu
mass of neutron is mn=1.0087 amu
atmomic number of 40Ca is Z=20
its mass number is A=40
so the mass defect is
Δm=(Zmp+(A-Z)mn)-m
=0.242 amu

But it says the correct answer is 0.367u, why? What am I doing wrong? Thanks.
 
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Δm=(Zmp+(A-Z)mn)-(m-Zme)
Now the formula looks better :)
 
Nvm, got it, thanks
 
Last edited:

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