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Calculating the mass in a solenoid system

  1. Jan 15, 2010 #1
    1. The problem statement, all variables and given/known data

    Through the bigger coil with N = 10,000 turns of wire and length of L = 30 cm is flowing electric current of I = 5 A. Inside the big coil we insert a smaller coil with
    N(1) = 500 turns, length of L(1) = 3 cm, and a radius r = 1 cm. The electric current flowing through the small coil is I(1) = 1 A. Axis of both coils are perpendicular to one another, smaller coil is rotatable around a rectangular axis (picture!). On the edge we attach a light string with the weight. What has to be the mass of the weight so that the small coil will not turn? In which direction do the electric currents I and I1 run?

    Picture: http://item.slide.com/r/1/227/i/hpQg_yax1D-i2BRLqRDiva38H-JMSI_x/ [Broken]

    2. Relevant equations

    B= (μ(0)*I*N)/ L
    M= p(m)*B
    r(m)= I*S*N

    3. The attempt at a solution

    First part: What has to be the mass of the weight so that the small coil will not turn?

    M= p(m)* [((μ(0)*I*N)/ L]

    M= (I(1)*π*r²*N(1)* μ(0)*I*N)/ L
    M(g)= m*(L(1)/2)*g

    M= M(g)
    (I(1)*π*r²*N(1)* μ(0)*I*N)/ L= m*(L(1)/2)*g
    m= (2*I(1)*π*r²*N(1)* μ(0)*I*N)/ (g*L*L(1))
    m= 2.2 kg

    Are my calculations correct?

    Thank you for helping!
     
    Last edited by a moderator: May 4, 2017
  2. jcsd
  3. Jan 15, 2010 #2

    rl.bhat

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    Homework Helper

    If there is no mass attached to the smaller coil, what will happen to the coil?
     
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